2x+3x^2-4=12

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Solution for 2x+3x^2-4=12 equation:


Simplifying
2x + 3x2 + -4 = 12

Reorder the terms:
-4 + 2x + 3x2 = 12

Solving
-4 + 2x + 3x2 = 12

Solving for variable 'x'.

Reorder the terms:
-4 + -12 + 2x + 3x2 = 12 + -12

Combine like terms: -4 + -12 = -16
-16 + 2x + 3x2 = 12 + -12

Combine like terms: 12 + -12 = 0
-16 + 2x + 3x2 = 0

Factor a trinomial.
(-8 + -3x)(2 + -1x) = 0

Subproblem 1

Set the factor '(-8 + -3x)' equal to zero and attempt to solve: Simplifying -8 + -3x = 0 Solving -8 + -3x = 0 Move all terms containing x to the left, all other terms to the right. Add '8' to each side of the equation. -8 + 8 + -3x = 0 + 8 Combine like terms: -8 + 8 = 0 0 + -3x = 0 + 8 -3x = 0 + 8 Combine like terms: 0 + 8 = 8 -3x = 8 Divide each side by '-3'. x = -2.666666667 Simplifying x = -2.666666667

Subproblem 2

Set the factor '(2 + -1x)' equal to zero and attempt to solve: Simplifying 2 + -1x = 0 Solving 2 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1x = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1x = 0 + -2 -1x = 0 + -2 Combine like terms: 0 + -2 = -2 -1x = -2 Divide each side by '-1'. x = 2 Simplifying x = 2

Solution

x = {-2.666666667, 2}

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